Answer:See below.Step-by-step explanation:[tex] f(x) = x^2 - 16 [/tex]Replace f(x) with y.[tex] y = x^2 - 16 [/tex]Switch x and y.[tex] x = y^2 - 16 [/tex]Solve for y.[tex] y^2 = x + 16 [/tex][tex] y = \pm\sqrt{x + 16} [/tex]Replace y with f^(-1)(x).[tex] f^{-1}(x) = \pm\sqrt{x + 16} [/tex]The relation above is not a function, so the given function f(x) does not have an inverse unless the domain is restricted.