The perimeter of a quadrilateral (four-sides polygon) is 50 inches. The longest side is three times as long as the shortest side. The other two sides are equally long and are 4 inches longer than the shortest side. Find the length of all four sides.
Accepted Solution
A:
The side lengths of quadrilateral are 21 inches; 11 inches; 11 inches; 7 inches.SOLUTION:Given, the perimeter of a quadrilateral (four-side polygon) is 50 inches. Let the length of shortest side be n inches. The longest side is three times as long as the shortest side. That is, length of largest side = 3n inchesThe other two sides are equally long and are 4 inches longer than the shortest side. Then, length of remaining two sides = 4 + n inches We have to find the length of all four sides.Now, we know that, perimeter = 50 inches [tex]\begin{array}{l}{\rightarrow \text { Sum of all sides }=50} \\\\ {\rightarrow n+3 n+n+4+n+4=50} \\\\ {\rightarrow n+3 n+n+n=50-4-4} \\\\ {\rightarrow 6 n=42} \\\\ {\rightarrow n=7}\end{array}[/tex]So, length of sides will be, [tex]7 \text { inches; } 3\times7=21 \text { inches; } 7+4=11 \text { inches; } 7+4=11 \text { inches. }[/tex]